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Drupady [299]
3 years ago
6

Chem Equations Balance and Classify each of the following equations into: Combination reaction, Decomposition Reacti

on, Single
Replacement reaction, Combustion reaction Double
Replacement reaction
A)
KBr(aq) + Cl2(g) → _ KCl(aq) + Br2(1)
B)
CaBr2(aq)
+ H2SO4(aq) - CaSO4(s) +_HBr(g)
N2(g) + H2(g) + NH3(g)
Grading: Each Equation Balanced --2 points, Classification --
1 point each
Ontime submission ---1 point
DUE: Oct 9, 2020 at 11:00 AM

Chemistry
1 answer:
Arlecino [84]3 years ago
3 0

Answer :

(A) The balanced chemical reaction will be:

2KBr(aq)+Cl_2(g)\rightarrow 2KCl(aq)+Br_2(l)

This reaction is a single replacement reaction.

(B) The balanced chemical reaction will be:

This reaction is a double displacement reaction.

(C) The balanced chemical reaction will be:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

This reaction is a combination reaction.

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of an element present on reactant side must be equal to the product side.

Part (A):

The balanced chemical reaction will be:

2KBr(aq)+Cl_2(g)\rightarrow 2KCl(aq)+Br_2(l)

This reaction is a single replacement reaction in which the most reactive element displaces the least reactive element from its solution.

Part (B):

The balanced chemical reaction will be:

CaBr_2(aq)
+H_2SO_4(aq)\rightarrow  CaSO_4(s)+2HBr(g)

This reaction is a double displacement reaction in which a positive cation and a negative anion of two reactants exchange their places to form two new products.

Part (C):

The balanced chemical reaction will be:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

This reaction is a combination reaction in which the two atoms combine to form a larger molecule.

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cbuck763
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A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

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7 0
3 years ago
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

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klemol [59]

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Nitella [24]

Answer:

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