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Drupady [299]
3 years ago
6

Chem Equations Balance and Classify each of the following equations into: Combination reaction, Decomposition Reacti

on, Single
Replacement reaction, Combustion reaction Double
Replacement reaction
A)
KBr(aq) + Cl2(g) → _ KCl(aq) + Br2(1)
B)
CaBr2(aq)
+ H2SO4(aq) - CaSO4(s) +_HBr(g)
N2(g) + H2(g) + NH3(g)
Grading: Each Equation Balanced --2 points, Classification --
1 point each
Ontime submission ---1 point
DUE: Oct 9, 2020 at 11:00 AM

Chemistry
1 answer:
Arlecino [84]3 years ago
3 0

Answer :

(A) The balanced chemical reaction will be:

2KBr(aq)+Cl_2(g)\rightarrow 2KCl(aq)+Br_2(l)

This reaction is a single replacement reaction.

(B) The balanced chemical reaction will be:

This reaction is a double displacement reaction.

(C) The balanced chemical reaction will be:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

This reaction is a combination reaction.

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of an element present on reactant side must be equal to the product side.

Part (A):

The balanced chemical reaction will be:

2KBr(aq)+Cl_2(g)\rightarrow 2KCl(aq)+Br_2(l)

This reaction is a single replacement reaction in which the most reactive element displaces the least reactive element from its solution.

Part (B):

The balanced chemical reaction will be:

CaBr_2(aq)
+H_2SO_4(aq)\rightarrow  CaSO_4(s)+2HBr(g)

This reaction is a double displacement reaction in which a positive cation and a negative anion of two reactants exchange their places to form two new products.

Part (C):

The balanced chemical reaction will be:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

This reaction is a combination reaction in which the two atoms combine to form a larger molecule.

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Soloha48 [4]

Answer:

I think C

Explanation:

because hydrogen on the right side only have two while on the left side it have 4

5 0
3 years ago
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What is the compound name for the ion chemical formula AgBr?
Gnom [1K]

Answer:

Silver bromide.

Explanation:

4 0
3 years ago
The density of aluminum is 2.70 g/mL. If you use 108 g of aluminum foil, what is its volume in mL?
Natali5045456 [20]

Answer:

volume =40.0 ml

Explanation:

density = mass/ volume

volume = mass/ density

volume = 108/ 2.70

volume =40.0 ml

3 0
3 years ago
To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

6 0
3 years ago
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
3 years ago
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