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3 years ago

To answer this question, you will read two articles. First, read Article 1.

Chemistry

2 answers:

Zina [86]3 years ago

7 0

Bro you really expect us to read that for just 5 points and we all be to lazy to read that

svp [43]3 years ago

3 0

???????????????????????)Help mys pLZ

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Calculate the pH of each of following buffered solutions.?a. 0.10 M acetic acid/0.25 M sodium acetate b. 0.25 M acetic acid/0.10

Masteriza [31]

Answer:

a. 5.10.

b. 4.35.

c. 5.10.

d. 4.35.

Explanation:

a. 0.10 M acetic acid/0.25 M sodium acetate

For acidic buffer:

∵ pH = pKa + log [salt]/[Acid]

∴ pH = - log(Ka) + log [salt]/[Acid]

Ka for acetic acid = 1.8 x 10⁻⁵.

∴ pH = - log(1.8 x 10⁻⁵) + log(0.25)/(0.10)

∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.

b. 0.25 M acetic acid/0.10 M sodium acetate

For acidic buffer:

∵ pH = pKa + log [salt]/[Acid]

∴ pH = - log(Ka) + log [salt]/[Acid]

Ka for acetic acid = 1.8 x 10⁻⁵.

∴ pH = - log(1.8 x 10⁻⁵) + log(0.10)/(0.25)

∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.

c. 0.080 M acetic acid/0.20 M sodium acetate

For acidic buffer:

∵ pH = pKa + log [salt]/[Acid]

∴ pH = - log(Ka) + log [salt]/[Acid]

Ka for acetic acid = 1.8 x 10⁻⁵.

∴ pH = - log(1.8 x 10⁻⁵) + log(0.20)/(0.08)

∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.

d. 0.20 M acetic acid/0.080 M sodium acetate

For acidic buffer:

∵ pH = pKa + log [salt]/[Acid]

∴ pH = - log(Ka) + log [salt]/[Acid]

Ka for acetic acid = 1.8 x 10⁻⁵.

∴ pH = - log(1.8 x 10⁻⁵) + log(0.08)/(0.20)

∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.

6 0

4 years ago

Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B

eimsori [14]

2 boxes of A
Because C = A + B
2 of A = 20 grams
at the other hand we have 2 of B = 10
So 20 + 10 = 30 grams

3 0

4 years ago

For a given reaction, ΔS = +106 J/mol ⋅ K, and the reaction is spontaneous at temperatures above the crossover temperature, 446

solniwko [45]

Answer: 47.276 kJ/mol

Explanation:

According to Gibb's equation:

$\Delta G=\Delta H-T\Delta S$

$\Delta G$ = Gibbs free energy

$\Delta H$ = enthalpy change

$\Delta S$ = entropy change = +106 J/mol

T = temperature in Kelvin = 446 K

$\Delta G$ = +ve, reaction is non spontaneous

$\Delta G$ = -ve, reaction is spontaneous

$\Delta G$ = 0, reaction is in equilibrium

$\Delta H=T\Delta S$

$\Delta H=446K\times +106J/Kmol=47276J/mol=47.276kJ/mol$ (1kJ=1000J)

Thus the value of ΔH = 47.276 kJ/mol, assuming that ΔH and ΔS do not vary with temperature.

7 0

3 years ago

In order for nuclear fusion to occur, the core of the sun must be hot enough to overcome the _________ of the nuclei. select one

andreyandreev [35.5K]

The answer is option a, that is " electromagnetic repulsions".
The sun generates energy by nuclear fusion, and converts a part of its mass into energy and nuclear fusion is the source of all energy that is released by the sun. The two things which are required for the process of nuclear fusion are high temperature and the high densities.

7 0

4 years ago

Transition metals when moving from left to right on the periodic table?

Ierofanga [76]

Answer:

True

Explanation:

5 0

3 years ago