Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
I’m pretty sure it’s A mid-ocean ridges
Unsaturation (IHD) 2 hydrogen Needed
IHD = [(2n+2) -H]/2
(H: X=1, N=-1, O= zero)
Unsaturation:
Double bonds = 1
Rings = 1
Triple Bonds = 2
The degrees of unsaturation in a molecule are additive — a
molecule with one double bond has one degree of unsaturation, a molecule with
two double bonds has two degrees of unsaturation, and so forth.
Kr look on periodic table it's krypton elements
Formula 1!!!!!!!!!!!!!!!!!!!!!!!!!!