Let K and T be the speeds of Kirk and Thor respectively.
Note the standard definition that d=vt, distance equals velocity times time.
t=d/v
For Kirk, t=525/(T+5)
For Thor, t=490/T
Since we are told that they have traveled the same amount of time we can say t=t which leaves us:
525/(T+5)=490/T multiply both sides by T
525T/(T+5)=490 multiply both sides by T+5
525T=490T+2450 subtract 490T from both sides
35T=2450 divide both sides by 35
T=70
So Thor's average speed is 70kph, since K=T+5
K=75kph
So Kirk's average speed is 75kph
Hello :
<span>y = –2x + 1 ....(1)
6x + 2y = 22 ....(2)
</span><span>by substitution in (2) : 6x+2(-2x+1) =22
6x-4x+2 = 22
2x =20
x =10
in(1) : y =-2(10)+1 = -19 </span>
Answer: it is the second option. Layla read 4 books in the first three months.
Step-by-step explanation: It completes the graph
Answer:
or
Step-by-step explanation:
Hello!
Use the quadratic formula:
First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0
3x² = 80
3x² - 80 = 0
Note, thats the value of b will be 0, as there is no "bx"
Now, solve:
- Plug in values
- Simplify the radical (Discriminant)
- Pull out perfect squares
- Reduce factors
The solutions are