Answer:
Step-by-step explanation:
g(5) = 5^2 - 4 = 25 - 4 = 21
f(21) = 5(21) + 2 = 105 + 2 = 107
A+b > c as in the side lengths
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,

, can be calculated as follows:
- the modulus of

is equal to the nth-power of the modulus of z, while the angle of

is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so

is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since

and both sine and cosine are periodic in

, (1) becomes
Answer:
23/50, 0.46, and 46%
Step-by-step explanation:
This problem is stating that every fifty times you flip a coin you get 23 heads. Finding the fraction is simple, it would be 23/50 because it is expressing the probability. The problem clearly states that every 50 times you get 23 heads. To find the decimal, take the fraction, 23/50, and multiply the numerator and denominator by 2. you get 46/100 which is 0.46. A percent is just a fraction out of a 100 which would make the percent 46.
Answer:

Step-by-step explanation:
Using the rule of exponents
=
, then
=
= 