35 out of 56 as a percentage

220-109.4 how to solve ?

anastassius [24]

Answer: 110.6

Step-by-step explanation: 220 - 109.4 = 110.6

7 0

3 years ago

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Diff. / Original amount= % of increase or decrease

V125BC [204]

Answer:

% increase = $\frac{\text{ Increased number -Original number }}{\text{Original number}} \times 100\%$

% decrease = $\frac{\text{ Original number - Decreased number }}{\text{Original number}} \times 100\%$

Step-by-step explanation:

Percentage Increase:

Let there be an original number. If it increased to a certain value we can calculate the percentage increase value with the help of following formula:

% increase = $\frac{\text{ Increased number -Original number }}{\text{Original number}} \times 100\%$

Percentage Decrease:

Let there be an original number. If it decreases to a certain value we can calculate the percentage decrease with the help of following formula:

% decrease = $\frac{\text{ Original number - Decreased number }}{\text{Original number}} \times 100\%$

6 0

3 years ago

In an apartment complex with 28 units, 19 of the renters keep a pet. What percentage does not keep a pet?

Aleks04 [339]

If 19 out of 28 renters keep a pet, there are $28-19 = 9$ renters who don't keep a pet.

Whenever you have a subset of some set, and you want to know which percentage of the set the subset represents, you simply have to compute

$\dfrac{\text{number of elements in the subset}}{\text{number of elements in the set}}\times 100$

So, in your case, you're wondering what percentage of 28 does 9 represent. So, the formula becomes

$\dfrac{9}{28}\times 100 = 0.32\overline{142857}\times 100 = 32.\overline{142857} \approx 32.14\%$

6 0

3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

7 0

3 years ago

What is the volume of a hemisphere with a radius of 26.7 m, rounded to the nearest tenth of a cubic meter?

attashe74 [19]

Answer:

$39,865.1m^3$

Step-by-step explanation:

a hemisphere is half a sphere.

And if the formula for the volume of a sphere is:

$V=\frac{4\pi r^3}{3}$

we must calculate the volume of the sphere and in the end divide by two to find the volume of the hemisphere.

Since the radius is:

$r=26.7m$

substituting this into the formula for volume:

$V=\frac{4\pi (26.7m)^3}{3} \\\\V=\frac{4(3.1416)(19,034.163m^3)}{3} \\\\V=79,730.12m^3$

this is the volume of the total sphere, thus the volume of a hemisphere is:

$\frac{V}{2}=\frac{79,730.12m^3}{2}\\ =39,865.06m^3$

rounding to the nearest tenth:

$39,865.1m^3$

8 0

3 years ago

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