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3 years ago

What do we mean when we say a chemical reaction is balanced? (Several choices can be correct.)

Chemistry

1 answer:

Rina8888 [55]3 years ago

3 0

Answer:

2 and 3

Explanation:

A chemical reaction is defined as the process in which two or more reactants combined together chemically and gives a different product.

A balanced chemical equation involves an equal number of atoms on the reactant and product side. A balanced chemical reaction occurs when the atoms present on the reactant side or left side of the arrow is equal to the atoms on the product side or right side of the arrow.

The process of the balanced chemical equation is based on errors and trials in which the atoms in each element is identified, the atoms are then multiplied with required numbers, the addition of coefficient in front of molecules and check the equation at last.

Hence, the correct options are "2 and 3".

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If the value of Kc for the reaction is 2.50, what are the equilibrium concentrations if the reaction mixture was initially 0.500

ratelena [41]

Answer: The equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

Explanation:

We are given:

Initial concentration of sulfur dioxide = 0.500 M

Initial concentration of nitrogen dioxide = 0.500 M

Initial concentration of sulfur trioxide = 0.00500 M

Initial concentration of nitrogen monoxide = 0.00500 M

The chemical reaction follows:

$SO_2+NO_2\rightleftharpoons SO_3+NO$

Initial: 0.500 0.500 0.005 0.005

At eqllm: 0.500-x 0.500-x 0.005+x 0.005+x

The expression of equilibrium constant for the above reaction follows:

$K_c=\frac{[SO_3][NO]}{[SO_2][NO_2]}$

We are given:

$K_c=2.50$

Putting values in above equation, we get:

$2.50=\frac{(0.005+x)\times (0.005+x)}{(0.500-x)\times (0.500-x)}\\\\x=0.304,1.37$

Neglecting the value of x = 1.37, because change cannot be greater than the initial concentration

So, equilibrium concentration of sulfur dioxide = $(0.500-x)=(0.500-0.304)=0.196M$

Equilibrium concentration of nitrogen dioxide = $(0.500-x)=(0.500-0.304)=0.196M$

Equilibrium concentration of sulfur trioxide = $(0.00500+x)=(0.00500+0.304)=0.309M$

Equilibrium concentration of nitrogen monoxide = $(0.00500+x)=(0.00500+0.304)=0.309M$

Hence, the equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.

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3 years ago

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The landscape feature that forms when plate movement forces the crust to bend downward is a.......

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2Fe +3S= Fe2S3 how many grams of sulfur are involved in this reaction if 95 grams of iron are needed to react with sulfur

Zepler [3.9K]

Answer:

83 g

Explanation:

Step 1: Write the balanced equation

2 Fe + 3 S ⇒ Fe₂S₃

Step 2: Calculate the moles corresponding to 95 g of Fe

The molar mass of Fe is 55.85 g/mol.

95 g × 1 mol/55.85 g = 1.7 mol

Step 3: Calculate the moles of S needed to react with 1.7 moles of Fe

The molar ratio of Fe to S is 2:3. The moles of S needed are 3/2 × 1.7 mol = 2.6 mol

Step 4: Calculate the mass corresponding to 2.6 moles of S

The molar mass of S is 32.07 g/mol.

2.6 mol × 32.07 g/mol = 83 g

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How many magnesiums are in 2mg2 O3

Doss [256]

There are two magnesium molecules or 4 atoms

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