Answer:
7.78×10¯³ mole
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 75 mL
Pressure (P) = 255 kPa
Temperature (T) = 22.5 °C
Number of mole (n) =?
Next, we shall convert 75 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
75 mL = 75 mL × 1 L / 1000 mL
75 mL = 0.075 L
Next, we shall convert 22.5 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 22.5 °C
Temperature (T) = 22.5 °C + 273
Temperature (T) = 295.5 K
Finally, we shall determine the amount of oxygen molecules present in steel calorimeter. This can be obtained as follow:
Volume (V) = 0.075 L
Pressure (P) = 255 kPa
Temperature (T) = 295.5 K
Gas constant (R) = 8.314 KPa.L/Kmol
Number of mole (n) =?
PV = nRT
255 × 0.075 = n × 8.314 × 295.5
19.125 = n × 2456.787
Divide both side by 2456.787
n = 19.125 / 2456.787
n = 7.78×10¯³ mole
Thus, amount of oxygen molecules present in steel calorimeter is 7.78×10¯³ mole
by looking at the periodic table I think Florian is a gas because it's important like in the bottom
Explanation:
Given the amount of fluorine is ---- 1.25 mol.
What is the mass of given fluorine in grams?
Since
To get the mass of the substance in grams, multiply the given number of moles with the molecular mass of the substance.
Hence, among the given options, the correct answer is the last option that is
Multiply the atomic mass of fluorine by 1.25.
True. These ions are of a 2- charge. Oxygen is an example. It will form a 2- charge if ionize.
Because some atoms<span> are more stable when they </span>gain or lose<span> an </span>electron<span> and </span>form ions<span>.</span>