"Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid
1 answer:
You might be interested in
Answer: 0.1161 grams of mercury(II) sulfide) form.
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
a) Molarity of solution = 0.10 M
Volume of solution = 0.020 L
Putting values in equation 1, we get:
b) Molarity of solution = 0.010 M
Volume of solution = 0.050 L
Putting values in equation 1, we get:
According to stoichiometry :
1 mole of reacts with 1 mole of
Thus 0.0005 moles of reacts with=
moles of
Thus is the limiting reagent and
is the excess reagent.
According to stoichiometry :
1 mole of forms= 1 mole of
Thus 0.0005 moles of forms=
moles of
mass of
Thus 0.1161 grams of mercury(II) sulfide) form.
<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>
In general, the gas equation can be written
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)
T = temperature, Kelvin
n = N / No
n = mole
No = Avogadro number (6.02.10²³)
n = m / MW
m = mass
MW = molecular weight
For density , can be formulated :
P = 327 mmHg = 0,430263 atm
R = 0.082 L.atm / mol K
T = 48 ºC = 321.15 K
MW of H₂ = 2.015 g/mol
The density :