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gregori [183]
3 years ago
6

"Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid

(HCl) is mixed with an aqueous solution of potassium hydroxide"
Chemistry
1 answer:
timurjin [86]3 years ago
3 0

Answer:

KOH(aq) + HCl(aq) ——-> KCl(aq) + H2O(l)

Explanation:

A neutralization reaction is the chemical reaction between an acid and an alkali to yield salt and water only.

In this particular question, the acid is hydrochloric acid while the alkali is potassium solution. We now write the equation of reaction as follows:

KOH(aq) + HCl(aq) ——-> KCl(aq) + H2O(l)

The salt formed here is KCl otherwise called potassium chloride

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sashaice [31]

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

It is known that at standard condition, vapor pressure is 760 mm Hg.

And, it is given that methanol vapor pressure in air is 88.5 mm Hg.

Hence, calculate the volume percentage as follows.

                  Volume percentage = \frac{\text{given vapor pressure}}{\text{standard vapor pressure}} \times 100

                                                    = \frac{88.5}{760} \times 100

                                                    = 11.65%

Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.

6 0
3 years ago
Scenario: You are testing two different
chubhunter [2.5K]

Answer:1 × 10-8 M

Explanation:

5 0
3 years ago
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Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.
Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n}{W_s}

where,

n = moles of solute

W_s = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg

Now put all the given values in the formula of molality, we get

Molality=\frac{0.241}{0.0137kg}=17.6mole/kg

Therefore, the molality of solution is 17.6 mole/kg

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3 years ago
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VII . A because it contains Br (l), Cl (g) and I (s)
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