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inn [45]
3 years ago
9

In 3-4 sentences, explain how you would determine if the solution is unsaturated, saturated or supersaturated?

Chemistry
2 answers:
mr Goodwill [35]3 years ago
7 0
You can determined if the solution is <span>unsaturated, saturated or supersaturated by adding more of the solute. If you add more solute to the solution and the solute is dissolved, then the solution is still unsaturated. If adding more solute would not dissolve the solute, then the solution is already saturated. However, when adding more solute, precipitation of the solute happens, then the solution is supersaturated.</span>
Lena [83]3 years ago
6 0

Answer :

Unsaturated solution : It is defined as the solution in which the more amount of solute particles can be dissolved in the solvent. For example : The salt in water or sugar in water is an unsaturated solution if they can dissolve the more amount of solute in them.

Saturated solution : It is defined as the solution in which there is no more amount of solute particles can be dissolved in the solvent.  For example : When we are adding sugar in the water until it no longer dissolves is a saturated solution.

Supersaturated solution : It is defined as the solution in which the more amount of solute particles is present than the solvent particles.  For example : The sugar syrup is an example of supersaturated solution.

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Calculate the percent yield of a reaction where a student collected 16.8 grams of product and was expecting to collect 49.7 gram
masya89 [10]

Answer:

\boxed{\text{33.8 \%}}

Explanation:

\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}

Data:

        Actual yield = 16.8 g

Theoretical yield = 49.7 g

Calculation:

\text{\% yield} = \dfrac{\text{16.8 g}}{\text {49.7 g}} \times\text{100 \%} = \boxed{\textbf{33.8 \%}}

8 0
3 years ago
Metallic bonds are found between two?
earnstyle [38]

Are found between two metals

8 0
4 years ago
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
4NaCl + 2SO2 + _____H2O + _____O2 → _____Na2SO4 + 4HCl
Alik [6]

The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.

BALANCING EQUATION:

  • Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.

  • According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl

  • Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:

4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl

Learn more at: brainly.com/question/21049751?referrer=searchResults

3 0
3 years ago
It is found that 250 ml of gas at stp has a mass of .675 g what is the molar mass
katrin2010 [14]

Answer:

61.3 g/mol  

Step-by-step explanation:

We can use the <em>Ideal Gas Law</em> to solve this problem:

       pV = nRT

Since n = m/M, the equation becomes

       pV = (m/M)RT     Multiply each side by M

    pVM = RT              Divide each side by RT

         M = (mRT)/(pV)

<em>Data: </em>

m = 0.675 g

R = 0.0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

p = 1 bar

V = 250 mL = 0.250 L

<em>Calculation: </em>

M= (0.675 × 0.083 14 × 273.15)/(1 × 0.250)

M= 15.33/0.250

M= 61.3 g/mol

4 0
3 years ago
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