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3 years ago

(5.7100,000)(1.91000,000)

Mathematics

1 answer:

Digiron [165]3 years ago

4 0

Answer: (5.7*10^5) = 570,000 and 1.9*10^6 = 1,900,000

so the answer is the sum o f it!

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it will take 65 days. 130 tubes of cookie dough.

Step-by-step explanation:

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3 years ago

Circle groups to show 4x(2x2).

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3 years ago

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Find the values of v,w,x,y,z

vichka [17]

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2 years ago

Last one!! I need the steps please! Will mark brainliest!

hoa [83]

Answer:

$h(t)=-6(t-2)^2+24$

Step-by-step explanation:

Given function:

$h(t)=-6t^2+24t$

where:

h = height (in feet)
t = times (in seconds)

Rewrite in the form $h(t)=a(t-h)^2+k$

The quickest way to do this is to expand $h(t)=a(t-h)^2+k$ and compare coefficients with the original function.

$\begin{aligned}h(t)& =a(t-h)^2+k\\ & = at^2-2aht+ah^2+k\end{aligned}$

Comparing coefficients with $h(t)=-6t^2+24t$

$\begin{aligned}\implies at^2& =-6t^2\\ a &=-6\end{aligned}$

$\begin{aligned}\implies -2aht & =24t\\ -2(-6)ht& =24t\\ 12ht & = 24t\\ 12h & = 24\\ h & = 2\end{aligned}$

$\begin{aligned}\implies ah^2+k & = 0\\(-6)(2)^2+k &=0\\ -24+k & =0\\ k &=24 \end{aligned}$

Therefore, substituting the found values into the equation:

$h(t)=-6(t-2)^2+24$

6 0

2 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicu

iren2701 [21]

Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>

$A\times B=\begin{vmatrix}i&j&k\\1&1&0\\0&1&1\end{vmatrix}$

$A\times B=i-j+k$

Let v $=A\times B=i-j+k$

$v==$

$r_0==$

$r=r_0+vt$

Substitute the values then we get

$r=+t$

$r=$

The parametric equation of the line

$x=x_0+at,y=y_0+bt,z=z_0+ct$

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$x=3+t,y=1-t,z=t$

The symmetric equation of the line is given by

$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$\frac{x-3}{1}=\frac{y-1}{-1}=z$

8 0

3 years ago

(5.7*100,000)(1.9*1000,000)

(5.7100,000)(1.91000,000)