Answer:
1 and 2
Explanation:
It is given that, force exerted by air is negligible in any way.
Also, it is given that channel is in the shape of a segment of a circle with its center at O.
When it is within the frictionless channel at position 'Q',
A gravity exerts force on the ball in the downward direction. On the other hand, the channel pointing from Q to O also exerts a force on the ball.
However, there is no any force in the direction of motion. On the other hand, he channel pointing from O to Q does not exert a force on the ball.
Answer: same
Explanation: They both weigh a kilogram and there is no friction
Explanation:
I assume the acceleration calculated in part (b) is the 3.33 m/s² from your other question.
Use Newton's second law to find the total force:
F = ma
F = (60,000 kg) (3.33 m/s²)
F = 200,000 N
Since there are 2 engines, the thrust from each is half of this:
F = 100,000 N
In reality, there are forces other than thrust. There are also drag forces (rolling friction and air resistance).
From Newton's second law, if we increase the mass and keep the force the same, the acceleration decreases. So it would take longer to reach the take-off speed.
A.The hiker had an easy, level trail from 11:00-12:00 and was able to travel the fastest during that time period.---> may be because this was indeed fastest stage
K12 student ! Brainlest ?
Answer:
275 kJ
Explanation:
KE = ½mv² = ½(1200)(25²) = 375,000