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Travka [436]
3 years ago
6

Alpa wants to change kilometers into a smaller metric unit she will have to

Physics
2 answers:
kirill115 [55]3 years ago
7 0
If you want to change kilometers in to metres you need to multiply it by 100.
DerKrebs [107]3 years ago
6 0

Answer:

Use Egyptian fractions in the calculations.

Explanation:

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4) A force of 500 N acts on an area of 0.05m2. Find the pressure in Pascal.
snow_tiger [21]

Answer:

pressure = force ie 500 N divided by area ie 0.05m².

p=f by a

p= 500n divided by 0.05 m²

p= 10,000 pascal

6 0
3 years ago
Which object is in static equilibrium
balu736 [363]

Answer:

The body is said to be in static equilibrium if the net force acting on a body at rest is zero.As the net force is zero,the body will not undergo motion.

Explanation:

3 0
3 years ago
Read 2 more answers
The creation of electricity in a coil of a wire through the movement of a magnet is called what?
emmasim [6.3K]

Answer:

D. Electromagnetic Induction.

Explanation:

6 0
3 years ago
An astronaut is taking a space walk near the shuttle when her safety tether breaks. What should the astronaut do to get back to
Alexxandr [17]

Answer:

option (c)

Explanation:

According to the newton's third law, for every action there is an equal and opposite reaction.

As the astronaut throw the tool away from the shuttle, it means the action force is in the direction away from the shuttle and according to Newton's third law, the reaction force is getting in the direction of shuttle.

3 0
4 years ago
If the mass of a wheel is increased by a factor of 7 and the radius is increased by a factor of 15, by what factor is the moment
inn [45]

Answer:

The moment of inertia will be increased by a factor of 1575

Explanation:

Let the moment of inertia of a wheel be given as;

I = \frac{1}{2} mr^2\\\\

where;

I is the moment of inertia of the wheel

m is mass of the wheel

r is radius of the wheel

when the mass is increased by a factor of 7 and the radius is increased by a factor of 15

I_1 = \frac{1}{2}mr^2\\ \\I_2 = \frac{1}{2}(7m)(15r)^2\\\\I_2 =  \frac{1}{2}(7m)(225r^2)\\\\I_2 = 7\times 225[\frac{1}{2}(mr^2)]\\\\I_2 = 1575[\frac{1}{2}(mr^2)]\\\\Recall, \frac{1}{2}(mr^2) = I_1 \\\\I_2 = 1575 I_1

Thus, the moment of inertia will be increased by a factor of 1575

3 0
3 years ago
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