Question

What is the magnitude of a point charge that produces a potential of -200V at a distance of 1.00 mm?

Answer 1

Answer:

$q=-2.22*10^{-11}C$

Explanation:

The potential produces by a point charge is given by:

$V=\frac{kq}{r}$

Here, k is the Coulomb constant, q is the signed magnitude of the point charge and r is the distance between the charge and the point at which the electric potential is measured. Solving for q:

$q=\frac{rV}{k}\\q=\frac{1*10^{-3}m(-200V)}{8.99*10^9\frac{V\cdot m}{C}}\\q=-2.22*10^{-11}C$