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2 years ago

A 2.72 A current flows through a wire for

Physics

1 answer:

agasfer [191]2 years ago

8 0

Current=2.72A=I
Time=t=9.88s
Charge=Q

$\\ \rm\longmapsto I=\dfrac{Q}{t}$

$\\ \rm\longmapsto Q=It$

$\\ \rm\longmapsto Q=2.72\times 9.88$

$\\ \rm\longmapsto Q=26.87C$

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An internal resistance of 5 ohm and a battery of 15 ohm is connected to a resistance of 20 ohm calculate the electric current

Allushta [10]

Answer:

.6 A

Explanation:

Battery 15 VOLTS

V = IR

V / R = I

15 / ( 5+20) = .6 amps

5 0

2 years ago

U = 3, 9 , v = 4, 2 (a) find the projection of u onto v. (b) find the vector component of u orthogonal to v.

ExtremeBDS [4]

Answer:

(a) At U = 3, 9 , v = 4, 2, the projection of u onto v is w1=<2,8>

(b)At U = 3, 9 , v = 4, 2, the vector component of u orthogonal to v is w2 = <4,-1>

Explanation:

The projection of u onto v is given by:

w1= projvu = (u⋅v||v||2)v

Given that u= <6,7> and v=<1,4>, we can find the projection of u onto v as shown below:

w1= projvu = (u⋅v||v||2v=(<6,7>⋅<1,4><1,4>⋅<1,)

=(6⋅1+7⋅41⋅1+4⋅4)<1,4>

=3417<1,4>

=<2,8>

Part B

The vector component of u orthogonal to v is given by:

Using the given vectors and the projection found in part (a), we can find the vector component of u orthogonal to v as shown below:

w2=u−projvu

=<6,7≻<2,8>

=<(6−2),(7−8)>

=<4,−1>

To learn more about vector component, click brainly.com/question/17016695

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1 year ago

A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret

I am Lyosha [343]

Answer:

The spring constant is 45.94 N/m.

Explanation:

Given that,

Length = 50 cm

Mass = 270 g

Stretching the spring = 24 cm

We need to calculate the spring constant

Using formula of energy

The change in potential energy equal to the change in kinetic energy.

$mgh=\dfrac{1}{2}kx^2$

Put the value into the formula

$270\times10^{-3}\times9.8\times50\times10^{-2}=\dfrac{1}{2}\times k\times(24\times10^{-2})^2$

$k=\dfrac{2\times270\times10^{-3}\times9.8\times50\times10^{-2}}{(24\times10^{-2})^2}$

$k=45.94\ N/m$

Hence, The spring constant is 45.94 N/m.

3 0

3 years ago

The focal length of a concave lens 13.3 cm.Calculate its power.

cricket20 [7]

Explanation:

Formula for finding power : 1/f

Substitution of values:

1 /13.3 = 0.07518 cm

Please mark it as Brainliest!

4 0

3 years ago

airplane in flight has a pressure difference between the lower and upper wing surface; this provides an upward force that balanc

Dvinal [7]

Answer:

4523.17365 Pa

Explanation:

m = Mass of plane = 77000 kg

F = Force = Weight = $mg$

g = Acceleration due to gravity = 9.81 m/s²

A = Total area of wings = 167 m²

The pressure difference would be

$\Delta P=\dfrac{F}{A}\\\Rightarrow \Delta P=\dfrac{77000\times 9.81}{167}\\\Rightarrow \Delta P=4523.17365\ Pa$

The pressure difference required to keep the plane aloft is 4523.17365 Pa

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3 years ago