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3 years ago

Find an equation that passes through the points (3,-2) and (-1,-4)

Mathematics

1 answer:

Neko [114]3 years ago

7 0

See https://web2.0calc.com/questions/i-m-confused_17.

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Solve for x: 1 < x + 3 < 4

Otrada [13]

Answer:

The answer is D

Step-by-step explanation:

$1 - 3 < x < 4 - 3 \\ - 2 < x < 1$

8 0

3 years ago

The transformation which will map triangle PQR onto P'Q'R is

Mazyrski [523]

Given:

The graph of triangle PQR and triangle P'Q'R'.

To find:

The transformation that will map the triangle PQR onto P'Q'R'.

Solution:

From the given graph it is clear that the triangle PQR is formed in II quadrant and its base lies on the negative direction of x-axis.

The triangle P'Q'R' is formed in IV quadrant and its base lies on the positive direction of x-axis.

This is possible it the figure is rotated 180 degrees about the origin.

Therefore, the correct option is A.

3 0

3 years ago

What is the inverse of y=pi/2+sin x

Alekssandra [29.7K]

Answer:

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

Step-by-step explanation:

The given function is

$y=\frac{\pi}{2}+\sin x$

To find the inverse of this function, we interchange x and y.

$x=\frac{\pi}{2}+\sin y$

we now solve for y.

$x-\frac{\pi}{2}=\sin y$

Take the sine inverse of both sides to obtain;

$\sin ^{-1}(x-\frac{\pi}{2})=y$

Hence the inverse of the given function is;

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

where $\frac{\pi}{2}-1\le x\le \frac{\pi}{2}+1$

6 0

3 years ago

Read 2 more answers

Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing grap

Arisa [49]

The local minima of $f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$ are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)

<h3>How to determine the local minima?</h3>

The function is given as:

$f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$

See attachment for the graph of the function f(x)

From the attached graph, we have the following minima:

Minimum = (-1.5, 0)

Minimum = (7.980, 609.174)

The above means that, the local minima are

(x, f(x)) = (-1.5, 0) and (7.980, 609.174)