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zheka24 [161]
4 years ago
9

4y^2-16 is that a square of the sum, square of a difference, a product of a sum and difference, or not a special product?

Mathematics
1 answer:
Sindrei [870]4 years ago
3 0
Das is differnce of 2 perfect squaes

for

a^2-b^2, that factors to (a-b)(a+b0


4y^2=(2y)^2
16=4^2


(2y)^2-(4)^2=(2y-4)(2y+4)
square of a differnce
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Molodets [167]
Week 1: $100
Week 2: $102
Week 3: $104.04
Week 4: $106.1208
Week 5: $108.243216
Week 6: $110.40808032
Week 7: $112.6162419264
Week 8: $114.868566764928
Total: $858.296905011328

(A=100[((1+0.02)^(8)-1)(/0.2)=858.29

Hope that helped!
5 0
4 years ago
Read 2 more answers
Joseph and Isabelle left Omyra’s house at the same time. Joseph jogged north at 8 kilometers per hour, while Isabelle rode her b
insens350 [35]

For this case the distance will be given by:

d ^ 2 = (12 * 1.5) ^ 2 + (8 * 1.5) ^ 2

Rewriting we have:

d ^ 2 = (18) ^ 2 + (12) ^ 2

d ^ 2 = 324 + 144

d ^ 2 = 468

d = root (468)

d = 21.63 Km

Answer:

1) She did not find the full distance each traveled in 1.5 hours.

2) She should have used 12 km for Joseph's distance and 18 km for Isabelle's distance.

4 0
3 years ago
Hellpp please! ASAPP!!
MArishka [77]

Answer:

m∠z= 58.7

Step-by-step explanation:

Remember, all triangles sum up to 180 degrees.

So, the equation would be: 31.3+90+m∠z= 180.

Step 1- Add to simplify.

(31.3+90)+m∠z= 180

121.3+m∠z= 180

Step 2- Subtract to both sides.

121.3+m∠z= 180

-121.3             -121.3

m∠z= 58.7

4 0
3 years ago
Three vertices of parallelogram ABCD are A(2,-6),B(-1,2),C(5,3).find the coordinates of vertex D
salantis [7]

Check the first picture below.


for a parallelogram, it has to have two pairs of parallel sides, so BC || AD and AB || CD.

if two lines are parallel, they have the same slope, namely the <u>same rise and run</u>.

notice, the line BC has a run of 6 and a rise of 1, <u>arrows in red</u>, therefore, AD must also have a run of 6 and a rise of 1, so if we move from A 6 units over and 1 up, we'd end up at point D.


now, for part atop

Check the 2nd picture, in a parallelogram, opposite sides are parallel and opposite angles are equal, so if WLP is 144°, then PNW is also 144°.

in a parallelogram, diagonals bisect each other, so each cut the other in halves, so if PM is 9 then MW is also 9 and thus PW is just 9+9=18.


now, about QRST.

notice what we said about a parallelogram above, thus


\bf 8x+13=11x-23\implies 8x+36=11x\implies 36=3x \\\\\\ \cfrac{36}{3}=x\implies \boxed{12=x} \\\\[-0.35em] ~\dotfill\\\\ 2y+12=4y-4\implies 2y+16=4y\implies 16=2y \\\\\\ \cfrac{16}{2}=y\implies \boxed{8=y}


so then TQ ==> 2(8) + 12 ==> 16 + 12 ==> 28.

∡Q ==> 8(12) + 13 ==> 96 + 13 ==> 109°.

and since in a parallelogram, adjacent interior angles add up to 180°, then ∡Q + ∡T = 180°.

∡T ==> 180 - 109 ==> 71°.

3 0
4 years ago
Plz I need help !!!!!!!!
crimeas [40]
Hey the image doesn't appear for me
4 0
4 years ago
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