Answer:
im guessing around 2/9
Step-by-step explanation:
Plug in 2 for t.
=> -16*(2^2) +80*2 +3
=> -16*4 +160 +3
=> -64+163
=> 99
Answer:
59.26.
Step-by-step explanation:
I think!
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.
I hope this helps, God bless, and have a great day!
Brainliest is always appreciated :)