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Anarel [89]
3 years ago
10

Write the product as a trinomial.

Mathematics
2 answers:
OlgaM077 [116]3 years ago
5 0
We'll use the FOIL method to multiply the factors.

FOIL
First, Outside, Inside, Last

Multiply the first terms, then the outside terms, then the inside terms, then the last terms.

First
<span>(2r – 5)(r + 10) 

</span>2r \times r = 2r^2
<span>
Outside
</span><span>(2r – 5)(r + 10) 

</span>2r \times 10 = 20r
<span>
Inside
</span><span>(2r – 5)(r + 10) 

</span>-5 \times r = -5r
<span>
Last
</span><span>(2r – 5)(r + 10) 

</span>-5 \times 10 = -50
<span>
The trinomial should now look like this:

</span>2r^2 + 20r - 5r - 50
<span>
Combine like terms:

</span>20r - 5r = 15r
<span>
The following trinomial will be your answer:

</span>\boxed{2r^2 + 15r - 50}<span>
</span>
Andru [333]3 years ago
3 0
First we multiply 2r*r and it gives us 2r^{2}. 

Then -5r, + 20r = 15r

Then -5*10 gives us -50.

So the answer is: 2r^{2}+15r-50
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Answer:

DUE= {0,10,12,18,19}

Step-by-step explanation:

The union of two sets is a set which contains all the elements of both the sets. thus DUE= {0,10,12,18,19}

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Which of the following ( 15, 20, 30, 57 ) is the product of exactly three different prime numbers?
Andrei [34K]

Answer:

30=2*3*5, so it's 30

Step-by-step explanation:

15=3*5, so it's not 15

20=2*2*5, so it's not 20

30=2*3*5, so it's 30

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Answer:

v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Step-by-step explanation:

The given formula is :

H=\dfrac{m(v^2-u^2)}{2gx}

We need to find the formula for v.

Cross multiplying the given formula.

H\times 2gx=m(v^2-u^2)

Dividing both sides by m. So,

\dfrac{H\times 2gx}{m}=\dfrac{m(v^2-u^2)}{m}\\\\(v^2-u^2)=\dfrac{H\times 2gx}{m}

Adding both sides by u².

(v^2-u^2)+u^2=\dfrac{H\times 2gx}{m}+u^2\\\\v^2=\dfrac{H\times 2gx}{m}+u^2\\\\\text{So},\\\\v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Hence, this is the required formula.

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I hope this helps you

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3 years ago
Read 2 more answers
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