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Mathematics

1 answer:

Lapatulllka [165]3 years ago

7 0

B is my answer........

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mr_godi [17]

Thanks for this!

Explanation:
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Happy Valentine’s Day!

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2 years ago

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Simplify this equation please.

Sauron [17]

$\dfrac{\csc^2\theta-3\csc\theta+2}{\csc^2\theta-1}$

Identity:

$\sin^2\theta+\cos^2\theta=1\implies1+\cot^2\theta=\csc^2\theta$

So we can rewrite the denominator to get

$\dfrac{\csc^2\theta-3\csc\theta+2}{\cot^2\theta}$

Multiply numerator and denominator by $\sin^2\theta$ . Several terms will cancel since $\sin\theta\csc\theta=1$ . Also, $\cot\theta=\dfrac{\cos\theta}{\sin\theta}$ . We get

$\dfrac{1-3\sin\theta+2\sin^2\theta}{\cos^2\theta}$

Factorize the numerator, and write $\cos$ in terms of $\sin$ in the denominator to factorize it further to get

$\dfrac{(1-\sin\theta)(1-2\sin\theta)}{\cos^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{1-\sin^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}$

The $1-\sin\theta$ factors cancel, leaving you with

$\dfrac{1-2\sin\theta}{1+\sin\theta}$

which you could simplify a bit further by writing

$\dfrac{1+\sin\theta-3\sin\theta}{1+\sin\theta}=1-\dfrac{3\sin\theta}{1+\sin\theta}$

3 0

4 years ago

Which of the following is true about figure ABCD

svetoff [14.1K]

Where is the picture? And what is true about it is that they are both letters and in Caps

5 0

3 years ago

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Consider the function f(x) = x2 and the function g(x) shown below. How will the graph of g(x) differ from the graph of f(x)? g(x

Lapatulllka [165]

Answer:

The graph of g of x would be more narrow then f of x.