3x=2(5x-1)=11
3x=10x-2=11
-10x -10x
-------------------
-7x=-2=11
+2 +2
------------------
-7x=13
----- ------
-7 -7
x= -1.9
B = 2 + 2H
A = 20 ft^2
H = H
Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20
Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.
Since b = 2h+2
b= 2(2.7) + 2
b= 5.4 + 2
b=7.4
I don't know where you got 4 and 10, but what I got is different.
This is. Pemdas. P is puntion. M mutupaTy d division a. Aadd s subtraant
