X_>-42
sorry, i cant do the arrow thing on my keyboard, but it’s the same arrow in the picture
Let
N--------> <span>members of the club
we know that
($192/(N+2)=3.20
192=(N+2)*3.20
3.20*N+6.40=192
3.20*N=192-6.40
N=185.60/3.20
N=58
the answer is
58</span>
Answer:
hcf:3x^3-6x^2+y^2-3x+54
lcm:2(x+3)(x^2-3x+9)(x^3-3x^2+9)(y^2-3x+9)
Answer:
the height after 2 seconds will be 128 feet
Step-by-step explanation:
Data provided in the question:
Initial velocity = 96 feet per second
The function of height of falling debris above the ground is given as:
h(t) = 96t - 16t²
A) To find height after time t = 2 seconds
substituting the value of time in the above function, we get
h(t) = 96 × 2 - 16 × 2²
or
h(t) = 192 - 16 × 4
or
h(t) = 192 - 64
or
h(t) = 128 feet
Hence,
the height after 2 seconds will be 128 feet
