Answer:- 3.84 grams
Solution:- Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.
From the density and volume we calculate the mass as:
mass = volume*density
= 46.1 g
From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.
The calculations could easily be done using dimensional analysis as:
= 3.84 g KBr
Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.
Answer:
The equillibrium constant Kc = 11.2233
Explanation:
Step 1:
aA + bB ⇔ cC + dD
with a, b, c and d = coefficients
Kc = equillibrium constant =( [C]^c [D]^d ) / ( [A]^a [B]^b)
Concentration at time t
[A] = 0.300 M
[B] =1.10 M
[C] = 0.450 M
Change :
A: -x
B: -2x
C: -x
The following reaction occurs and equillibrium is established
A + 2B ⇔ C
[A] = 0.110M
[B] = ?
[C] = 0.640 M
For A we see that after change: 0.3 -x = 0.11
Then for B we have 1.1 - 2x = ? ⇒ 1.1 -2 *0.19 = 0.72
This gives us for the equillibrium constant Kc = [C] / [A][B] ²
Kc = 0.64 / (0.11) * (0.72)² = 11.2233
If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability. Example of an unstable atom with a single electron in its outer-most shell. ... In covalent bonds, atoms share electrons to achieve stability.
Hope this helped!
Answer:
biphenyl, benzyl alcohol, benzoic acid
Explanation:
Due to the nonpolar nature of cyclohexane, biphenyl will be the first solute to be eluted due to the presence of two phenyl rings. The second solute to be eluted will be benzyl alcohol due to the presence of OH group. This is because it has the ability to exhibit hydrogen bond with the silica column of the chromatography. Lastly, the benzoic acid will be the third solute to be eluted due to the presence of COOH group which is more polar than the OH group. Therefore, the order of elution of the components in the mixture is biphenyl, benzyl alcohol, benzoic acid.
I think it might be B, and A
