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3 years ago

the grocery store sells ground beef that is labeled 20% fat. How many grams of fat would be labeled in 1.3 pounds of ground beef

Chemistry

1 answer:

VladimirAG [237]3 years ago

5 0

Answer:

Grams of fat would be labeled in 1.3 pounds of ground beef are :

= 117.94 grams

Explanation:

STEP 1: Convert pound into grams:

1 pound = 453.6 grams (learn this)

STEP 2 : Calculate the number of grams in 1.3 pound.

Multiply the number by 1.3

1.3 pound = 1.3 x 453.6 grams

1.3 pound = 589.68 grams

STEP 3: Calculate the mass in 20 % percentage of sample.

$20\% of\ x=x\times \frac{20}{100}$

Here x = 589.68 grams

$20\%\ of\ 589.68 =589.68\times \frac{20}{100}$

$20\%\ of\ 589.68 =117.93grams$

= 117.94 grams

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An aqueous solution of barium hydroxide is standardized by titration with a 0.110 M solution of hydrochloric acid. If 29.5 mL of

Natali5045456 [20]

Answer:

0.02685 M is the molarity of the barium hydroxide solution.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ba(OH)_2$ mm.

We are given:

$n_1=11\\M_1=0.110 M\\V_1=14.4 mL\\n_2=2\\M_2=?\\V_2=29.5 mL$

Putting values in above equation, we get:

$1\times 0.11 M\times 14.4 mL=2\times M_2\times 29.5 mL$

$M_2=\frac{1\times 0.11 M\times 14.4 mL}{2\times 29.5 mL}=0.02685 M$

0.02685 M is the molarity of the barium hydroxide solution.

8 0

3 years ago

What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?

Viefleur [7K]

Data:
Molar Mass of NaOH = 40 g/mol

Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules

1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules

6.02*10²³y = 0.270*10²³
$y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}$
$\boxed{y \approx 0.04\:mol}$

Solving: Find the mass value now

40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH

$x = 40*0.04$
$\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark$

Answer:
The mass is 1.6 grams

6 0

3 years ago

Nickel has an FCC structure and an atomic radius of 0.124 nm. (12 points) a. What is the coordination number? b. Calculate the A

LekaFEV [45]

Answer:

a)CN=12

b)APF=74 %

c)a=0.35 nm

d)ρ=9090.9 $Kg/m^3$