4x/x^2-3x-18 - 2x/x^2+6x+9

2 answers:

8 0

$\bf \cfrac{4x}{x^2-3x-18}-\cfrac{2x}{x^2+6x+9}\qquad 
\begin{array}{lcclll}
x^2&-3x&-18\\
&\uparrow&\uparrow \\
& -6+3&-6\cdot 3\\\\
--&--&--\\\\
x^2&+6x&+9\\
&\uparrow &\uparrow \\
&3+3&3\cdot 3
\end{array}\\\\
-----------------------------\\\\
\cfrac{4x}{(x-6)(x+3)}-\cfrac{2x}{(x+3)(x+3)}\qquad LCD\to (x-6)(x+3)(x+3)
\\\\\\
\cfrac{4x(x+3)-2x(x-6)}{(x-6)(x+3)(x+3)}\implies \cfrac{4x^2+12x-2x^2+12x}{(x-6)(x+3)(x+3)}
\\\\\\
\cfrac{2x^2+24x}{(x-6)(x+3)(x+3)}\implies \cfrac{2x(x+12)}{(x-6)(x+3)(x+3)}$

vekshin13 years ago

4 0

A good math calculator is called math-way it shows step by step answers. I hope this helps

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8 0

3 years ago

Someone help me out with this my grade are bad

eduard

Answer:

2 units tall by 1 unit wide

Step-by-step explanation:

On the given rectangle it tell you the conversion to m is 1 unit = 2 m.

The new figure that needs to be drawn has a conversion of 1 unit = 8m.

So, the fist thing we need to do is calculate the m on the width at the height of the original, which is 16 by 8.

looking at this we can now convert this measurement into our new conversion of 1 unit = 8 m. We can do this by dividing the height and width separately.

Ex:

Since 16 is divided by 8 two times so that gives us the answer of 2 units.

8 is divisible by 8 one time so that gives us the width of 1 unit

if this is confusing just think of it like: x= $\frac{16}{8}$ for the height or x = $\frac{8}{8}$ for the width.