Well let's say that to compare these two numbers, we have to start with the definition first.
<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>
Looks like we can use any x-values right? Nope.
The value of x only applies to any positive real numbers for one reason.
As we know, any numbers time itself will result in positive. No matter the negative or positive.
<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>
Where b is the result from a×a. Let's see an example.
<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>
So basically, their counterpart or opposite still gives same value.
Then you may have a question, where does √-1 come from?
It comes from this equation:
When we solve the quadratic equation in this like form, we square both sides to get rid of the square.
Then where does plus-minus come from? It comes from one of Absolute Value propety.
<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>
Solving absolute value always gives the plus-minus. Therefore...
Then we have the square root of -1 in negative and positive. But something is not right.
As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.
Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.
Then we have another number which is -√1. This one is simple.
It is one of the solution from the equation y^2 = 1.
We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.
<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>
So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.