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Tatiana [17]
3 years ago
9

Mr. Cooper is building a playset in his backyard for his kids. He has a made a scale drawing of the playset to help him estimate

the amounts of building materials he needs to purchase. Part of the playset includes a rectangular sandbox, which has a length of 5 feet and a width of 7 feet. On the scale drawing, the length of the sandbox is 2 A. The scale used in the drawing is = 1 foot. B. On the scale drawing, the width of the sandbox is inches. C. If Mr. Cooper decides to make a new scale drawing of the playset, in which he uses a scale of inch = 1 foot, all of the dimensions in the old drawing will be multiplied by a factor of .
Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:

If Mr. Cooper decides to make a new scale drawing of the play set, in which he uses a scale of inch = 1 foot, all of the dimensions in the old drawing will be multiplied by a factor of ⇒ the last answer

Step-by-step explanation:

* Lets study what is the meaning of the scale factor

- To find a scale factor between two similar figures

# Find two corresponding sides and write the ratio of the two sides.

# If you begin with the smaller figure, your scale factor will be less

  than one.

# If you begin with the larger figure, your scale factor will be greater

  than one

* Now lets solve the problem

- The rectangular sandbox, has a length of 5 feet and a width of

  7 feet

- On the scale drawing, the length of the sandbox is 2 inches

- The actual sandbox and the drawing sandbox are similar

∵ The length of the actual sandbox is 5 feet

∵ The drawing length is 2 inches

∵ 1 foot = 12 inches

∴ The scale factor is 2/(5 × 12) = 1/30

* That means each actual dimensions will multiply by 1/30 to find

  the drawing dimensions

∴ The drawing length of the sandbox = 5 × 12 × 1/30 = 2 inches

∴ The drawing width of the sandbox = 7 × 12 × 1/30 = 2.8 inches

* All of the dimensions in the old drawing will be multiplied by

 a factor of 1/30

Rus_ich [418]3 years ago
4 0

Answer: 2?

Step-by-step explanation:

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SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
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