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Trava [24]
2 years ago
15

A rectangular prism has a height of 20 cm, length of 7 cm and width of 5 cm.

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
7 0
Formula for volume is:

width x length x height

5 x 7 x 20

5x7 = 35
35x20= 700
Answer is 700 cm^2
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Evaluate each expression if a = 4.1, b = 5.7, and c=0.3.<br> 4. a+b-c <br> 5. 10-(a+b)<br> 6. B- c+2
posledela

Answer:

  • a+b-c = 9.5
  • 10-(a+b) = 0.2
  • b-c+2 = 7.4

Step-by-step explanation:

4)

Given the expression

a+b-c

  • a=4.1
  • b=5.7
  • c=0.3

substituting the values in the expression

a+b-c = 4.1+5.7-0.3

          =  9.8 - 0.3

          = 9.5

5)

Given the expression

10-(a+b)

  • a=4.1
  • b=5.7
  • c=0.3

substituting the values in the expression

10-(a+b) = 10 - (4.1+5.7)

              = 10 - 9.8

              = 0.2

6)

Given the expression

b-c+2

  • a=4.1
  • b=5.7
  • c=0.3

substituting the values in the expression

b-c+2 = 5.7 - 0.3 +2

          = 5.4 + 2

           = 7.4

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Write a rule for the nth term of the arithmetic sequence. -23,-30,-37,-44...
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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