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Makovka662 [10]
4 years ago
8

HELP ASAP PLEASE HELPPPPPPP PLEASE

Mathematics
1 answer:
ella [17]4 years ago
5 0

Answer:

5 times 3

Step-by-step explanation:

you do 5 time 3. it is 15

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Can someone help me solve this?
Sergio [31]

Answer:

m<c = 104°

m<d = 80°

Step-by-step explanation:

Recall: Opposite angles of a cyclic quadrilateral are supplementary. Therefore, their sum equals 180°. Thus:

m<c + 76° = 180°

m<c + 76° - 76° = 180° - 76° (subtraction property of equality)

m<c = 104°

m<d + 100° = 180°

m<d +100° - 100° = 180° - 100° (subtraction property of equality)

m<d = 80°

8 0
3 years ago
Find the key features of the equation and graph it. (Can you explain how to find them and not just the answers please)
Vadim26 [7]

Given a function in a table or in algebraic or graphical form, identify key features such as x- and y-intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; and end behavior. Use key features of an algebraic function to graph the function.

7 0
2 years ago
Plz help duke for 10 points
BaLLatris [955]

Answer

A) 2(4+5)

2(9)

18

B) 2(10+2)

2(12)

24

C) 4*5

20

D) 10*2

20

7 0
3 years ago
A laptop computer is purchased for $2700. Each year, it’s value is 70% of its value the year before after how many years will la
n200080 [17]

<u>Answer:</u> 5 years!

<u>Reasoning:</u>

Year 1: 2700 x .70=1890

Year 2: 1890 x .70= 1323

Year 3: 1323 x .70= 926.1

Year 4: 926.1 x .70= 648.27

Year 5: 648.27 x .70=453.79

3 0
3 years ago
Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab
zhenek [66]

Answer:

test statistic is ≈ -0.36

p-value is  ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • sample mean driving distance (233.8 yards)
  • M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
  • s is the standard deviation (46.6 yards)
  • N is the sample size (192)

Then test statistic is z=\frac{233.8-235}{\frac{46.6}{\sqrt{192} } } =-0.3568

p-value is  0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

6 0
4 years ago
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