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Andreyy89
3 years ago
5

Evaluate f(-1) for the function f(x) = -5x + 3 *

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

f(-1) = 8

Step-by-step explanation:

f(-1) = x

f(-1) = -5(-1) + 3

f(-1) = 8

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4x + 8y= -8 <br> X= -2y + 1
slavikrds [6]

Answer:

Step-by-step explanation:

8 0
3 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
3 years ago
Five line segments coincide at a point as shown.
Nikitich [7]

Answer:

720º

Step-by-step explanation:

We can use vertical angles to figure this out. We can see that each of the unmarked angles in the triangles is a vertical angle to an empty space. A full circle has the measure of 360º. We need half of that which is 180º.

The sum of the angle measures of a triangle is 180º. We have five triangles so the total angle meaure is 900º.

However, we need to subtract the 180º to get 720º.

8 0
2 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
Find 759 ÷ 3. PLS I NEED HELP ITS EITHER HAS A REMAINDER OR NOT ALSO GIVE ME AN ANSWER PLS DIS DUE TODAY
omeli [17]

Answer:

253

Step-by-step explanation:

7 0
3 years ago
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