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Maksim231197 [3]
3 years ago
5

PLEASE HELP QUICK 10 POINTS AND I GIVE BRAINLEIST!!! what is the GCF of 110 and 132

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer: 22 because 2x 11 = 22

Hope I helped

Pls give me brainlist.

Step-by-step explanation:

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Which of the following statements is CORRECT? a. A graph of the SML as applied to individual stocks would show required rates of
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Hope this helps :)

5 0
3 years ago
If 40 men took 10 minutes to make 200 toys,how many man will take 40 minutes to make 350 toys?
Viktor [21]
40=4×10=200 toys
160=4×40=350 toys
7 0
3 years ago
Some of Mrs. Turay’s eighth graders took the PSAT test. Score totals of ten of her students are below. Calculate the mean and th
den301095 [7]

Answer:

(a) Mean=74

(b) Median=70

(c) The best measure of center= Median.

Step-by-step explanation:

We have been given a data set of PSAT scores of Mrs. Turay's eight graders. We are asked to find mean and median of the given data set.

(a) Let us find mean of data set by dividing the sum of given scores by the number of students.

\text{Mean}=\frac{60+62+67+69+70+70+71+75+76+120}{10}

\text{Mean}=\frac{740}{10}=74

Therefore, the mean test score will be 74.

(b) Now let us find median of our given data set. We have been given that number of students is 10, therefore, our median will be the average of 5th and 6th term.

60, 62, 67, 69, 70, 70, 71, 75, 76, 120.

We can see that 5th term is 70 and 6th term is 70 as well.

\text{Median}=\frac{70+70}{2}

\text{Median}=\frac{140}{2}

\text{Median}=70

Therefore, the median test scores will be 70.

(c) We can see that our data set has an outlier score as 120, which has increased the mean. Mean score is greater than median score. Since median is not affected by extreme value outliers, therefore, median will be the best measure of center for given test scores.    


3 0
4 years ago
Read 2 more answers
Can you please help me with A and B
svetoff [14.1K]
I read:
Farm Maid Yogurt : 6 g of fat in 13 cups
Dairy Delight Yogurt: 5 g of fat in 11 cups.

(This is what I read, which does not represent realistic numbers, likely decimals are missing).

(a) Farm Maid Yogurt
6 g/13 cups = 10 g/x cups
Cross multiply: 6x = 130 => x=130/6=21.67 cups.

(b)
Farm maid : 6 g/13 cups, 6/13 in 13/13 cups => 0.4615 g/cup
Dairy Delight : 5 g / 11 cups, 5/11 in 11/11 cups => 0.4545 g/cup
=> Dairy Delight Yogurt has slightly less fat.

(c) 9 cups of Dairy Delight
5 g / 11 cups = x g / 9 cups
Cross multiply
11x=5*9 g => x=5*9/11 g = 4.09 g

(d) 3 cups of Dairy Delight & 5 cups of Farm Maid.
5 g/ 11 cups = x g / 3 cups 
Cross multiply
x=5*3/11 = 1.3636 g

5 cups of Farm Maid
6 g / 13 cups = y g / 5 cups
Cross multiply
y=6*5/13=2.3077 g

Total fat consumed = 1.3636+2.3077 g = 3.6713 = 3.671 g (to the nearest thousandth gram).


4 0
3 years ago
(Help me quick!!!! Please Only have 10 minutes)
Elan Coil [88]
YOU DID NOT ATTACH ANY FILES type the question in the comments
5 0
3 years ago
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