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3 years ago

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Mathematics

2 answers:

Debora [2.8K]3 years ago

5 0

Answer:

1) 5p - 4 2) -4n - 3 3) -55b -58 4) -41p + 22 5) 24n - 40 6) -4x - 6

Step-by-step explanation:

1) 3(2p - 4) - (p + 8)= 6p - 12 - p + 8 = 5p - 4

2) -3(n + 3) - (n - 6)= -3n - 9 - n + 6 = -4n - 3

3) -4(7 + 5b) - 5(7b + 6)= -28 - 20b - 35b - 30 = -55b -58

4) 8(2 - 5p) - (p - 6)= 16 - 40p - p + 6 = -41p + 22

5) 8(n + 2) + 8(2n - 7)= 8n + 16 + 16n - 56 = 24n - 40

6) -(6x + 4) - 2(-x + 1)= -6x - 4 + 2x - 2 = -4x - 6

rosijanka [135]3 years ago

3 0

Answer:

In photomath

Step-by-step explanation:

1.) 6p-12 or 6(p-2)

2.) -4n-3

3.)-58-55b

4.) 22-41p

5.)8(3n-5) or 24n-40

6.)-2(2x+3) or -4x-6

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sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

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If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

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and so putting everything together, we get $f(t)$ :

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