2 committees. 6 is divisible by 3 twice, 8 is divisible by 4 twice.
Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence

here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now 
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.
Answer:
(2 + 5) / (9 - 4)
Step-by-step explanation:
"sum of 2 and 5" = (2 + 5)
"difference of 9 and 4" = (9 - 4)
"sum of 2 and 5 is divided by the difference of 9 and 4"
= (2 + 5) / (9 - 4)
A) Your primary concerns are the points B and E, so y> .5x+4 and y>or= x-4B) choose one or both points, and enter them into the equations. If the statements are true, then the equations work
for problem C So, any point in the shaded area, but not on the line, are valid points for Natalie's school