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barxatty [35]
3 years ago
12

Find the solution to the system of equations given below using substitution. PLEASE ANSWER QUICKLY

Mathematics
1 answer:
irinina [24]3 years ago
5 0

Answer:

option D

D. x = 5, y = 2

Step-by-step explanation:

Given in the question two equation,

Equation 1

5.3x + y = 28.5

Equation 2

4.2x + 3.1y = 27.2

rearrange equation 1 in terms of y

y = 28.5 - 5.3x

Substitute the value of y in equation 2

<h3>4.2x + 3.1(28.5 - 5.3x) = 27.2</h3>

4.2x + 88.35 - 16.43x = 27.2

4.2x - 16.43x = 27.2 - 88.35

-12.23x = -61.15

x = 61.15/12.23

x = 5

put value of x in any of the equation

<h3>5.3(5) + y = 28.5</h3>

y = 28.5 - 26.5

y = 2

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So I'm in an online class of geometry and one of the units is trig. but no matter how long i keep learning or trying to learn th
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Answer and explanation:

There are six main trigonometric ratios, namely: sine, cosine, tangent, cosecant, secant, cotangent.

Those ratios relate two sides of a right triangle and one angle.

Assume the following features and measures of a right triangle ABC

  • right angle: B, measure β
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  • angle C: measure γ
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Then, the trigonometric ratios are:

  • sine (α) = opposite leg / hypotenuse = a / b
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  • tangent (α) = opposite leg / adjacent leg = a / c

  • cosecant (α) = 1 / sine (α) = b / a
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Then, if you know one angle (other than the right one) of a right triangle, and any of the sides you can determine any of the other sides.

For instance, assume an angle to be 30º, and the lenght of the hypotenuse to measure 5 units.

  • sine (30º) = opposite leg / 5 ⇒ opposite leg = 5 × sine (30º) = 2.5
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Answer:

\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}

Step-by-step explanation:

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When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

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\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

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