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Irina-Kira [14]
3 years ago
7

Help with this thing ??

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

1/4

Step-by-step explanation:

I'm not sure if he wants the Dilution factor or the scale but anyway

CBA = 4 C'B'A'

Scale 1/4

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Name the property shown by each statement.
Lelechka [254]
The answer is a i believe
4 0
3 years ago
Read 2 more answers
Let f(x) = 16 - x^2, g(x) = 4 - x. Find (fg)(x) and its domain.
timofeeve [1]

Answer:

(fg)(x) = x^3-4x^2-16x+64, D: All Real Numbers

Step-by-step explanation:

(fg)(x) = f(x) x g(x)

= 16-x^2(4-x)

=64-16x-4x+x^3

(fg)(x) = x^3-4x^2-16x+64

Domain is all real numbers because you can substitute any real number for x and the function would still work.

5 0
3 years ago
tom drives 200 miles in 4 hour. he drives the first 32 miles at an average speed of 64mph. work out his average sped for the res
WINSTONCH [101]

Answer:

His average speed for the rest of the journey was of 48mph.

Step-by-step explanation:

We use the following relation to solve this question:

v = \frac{d}{t}

In which v is the velocity, d is the distance and t is the time.

First 32 miles at an average speed of 64mph.

So the time for these 32 miles is:

64 = \frac{32}{t}

64t = 32

t = \frac{32}{64}

t = 0.5

Rest of the trip:

200 - 32 = 168 miles in 4 - 0.5 = 3.5 hours. So the average speed is of:

v = \frac{d}{t} = \frac{168}{3.5} = 48

His average speed for the rest of the journey was of 48mph.

3 0
3 years ago
The expression x3 – 64 can be written as (x)3 – (4)3. What is the factorization of x3 – 64?
Sergio [31]
By factoring x^3-64 put you should get the second option as your answer

(x-4)(x^2+4x+16)
5 0
3 years ago
Read 2 more answers
A catering company provides packages for weddings and for showers. The cost per person for small groups
Tomtit [17]

Using the <em>normal distribution and the central limit theorem</em>, it is found that the probability the mean cost of the weddings is more than the mean cost of the showers is of 0.9665.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.
  • When two variables are subtracted, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances.

<h3>What is the mean and the standard error of the distribution of differences?</h3>

For each sample, they are given by:

\mu_W = 82.3, s_W = \frac{18.2}{\sqrt{9}} = 6.0667

\mu_S = 65, s_S = \frac{17.73}{\sqrt{6}} = 7.2382

For the distribution of differences, we have that:

\mu = \mu_W - \mu_S = 82.3 - 65 = 17.3

s = \sqrt{s_W^2 + s_S^2} = \sqrt{6.0667^2 + 7.2382^2} = 9.4444

The probability the mean cost of the weddings is more than the mean cost of the showers is P(X > 0), that is, <u>one subtracted by the p-value of Z when X = 0</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0 - 17.3}{9.4444}

Z = -1.83

Z = -1.83 has a p-value of 0.0335.

1 - 0.0335 = 0.9665.

More can be learned about the <em>normal distribution and the central limit theorem</em> at brainly.com/question/24663213

5 0
2 years ago
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