Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the
speed of the other, and that is why it arrived at the suburb 2 hour earlier than the other car. Find the speeds of both cars.
1 answer:
Answer:
Explanation:
<u>1. Data:</u>
i) Distance traveled by the cars:
ii) Speed of the cars:
iii) Time to arrive at the suburb:
- t₂ - t₁ = 2 hour ⇒ t₂ = t₁ + 2
<u>2. Equations:</u>
time = distance / speed
- t₂ = 480 / v₂
- t₁ = 480 / v₁ = 480 / (v₂ + 20)
t₂ - t₁ = 2 hour
↓ ↓ ↓
480/v₂ - 480/ (v₂ + 20) = 2
<u>3. Solve the equation</u>
480(v₂ + 20) - 480(v₂) = 2 × (v₂ + 20) (v₂)
240(v₂ + 20) - 240(v₂) = (v₂ + 20) (v₂)
240v₂ + 4800 - 240v₂ = (v₂)² + 20v₂
(v₂)² + 20v₂ - 4800 = 0
(v₂ + 80) (v₂ - 60) = 0
v₂ = - 80
v₂ = 60
Only the positive solution has physical meaning:
- v₁ = 60km/h + 20km/h = 80km/h ← answer
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