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Misha Larkins [42]
3 years ago
7

Please help me solve this

Mathematics
1 answer:
REY [17]3 years ago
6 0
The answer is ............... 21
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Letp,qandrbe the propositions such that,p:"You get an A on the final exam"q:"You do every exercise in this book"r:"You get an A
Zanzabum

Answer:

a) r→q

b) r→p

c) r→p

d) r→ p∧q

e) r→ p∨q

Step-by-step explanation:

Using logical connectives, as shown in the picture below, we can write all of the statements of the question.

p:"You get an A on the final exam"

q:"You do every exercise in this book"

r:"You get an A in this class"

a) r→q

b) r→p

c) r→p

d) r→ p∧q

e) r→ p∨q

6 0
3 years ago
Ill give brainliest please help :(
OleMash [197]

Answer:

okay so god,dog,now,won,noon,doom,mood,not,ton,pool

Step-by-step explanation:

7 0
3 years ago
Determine the missing information in the paragraph proof.
iren [92.7K]

Answer:

The answer is A.

Step-by-step explanation:

(StartFraction d minus b Over c minus a EndFraction) (StartFraction c minus a Over negative d + b EndFraction) = negative 1

7 0
3 years ago
Read 2 more answers
The mean of six test scores is 83.what is the sum of the six test scores?
Fittoniya [83]
Mean = total score : frequency
mean x frequency = total score

so
83 = total score : 6
83 × 6 = total score
498 = total score

so the sum of the 6 test scores is 498
6 0
3 years ago
31. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
Whitepunk [10]

Answer:

The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

and f(5)=1. linear equation of the line in the form

$$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

This means that the function f(x) satisfies the points (-1,4) and (5,1).

Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

$(y-1)=\frac{-1}{2}(x-5)$

Distribute $\frac{-1}{2}$,

$y-1=\frac{-1}{2} x+\frac{5}{2}$

Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$$

So, this is the required linear equation.

8 0
2 years ago
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