All categories

3 years ago

Find the 8th term of the arithmetic sequence -2x+5−2x+5, -7x+8−7x+8, -12x+11, ...

Mathematics

1 answer:

miss Akunina [59]3 years ago

7 0

Answer:

-37x+26

Step-by-step explanation:

The x-coefficients have the sequence ...

-2, -7, -12, ...

which has first term -2 and common difference of (-7 -(-2)) = -5. Then the 8th x-coefficient is ...

-2 + (-5)(8 -1) = -37

The constants have the sequence ...

5, 8, 11, ...

which has first term 5 and common difference 8 -5 = 3. Then the 8th constant term is ...

5 +(3)(8 -1) = 26

The 8th term of the sequence is -37x +26.

_____

The general term of an arithmetic sequence with first term a1 and common difference d is ...

an = a1 +d(n -1)

In the above, we have used n=8 to find the 8th term.

You might be interested in

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)<br><br>PLEASE HELP!

EleoNora [17]

Answer:

$\bold {$\dfrac{7}{44}$}$

Step-by-step explanation:

<h3> Reciprocal:</h3>

$\sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$ = $\dfrac{2}{11}$}$

<h3>Additive inverse:</h3>

$\text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}$

Now multiply,

$\sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\$

$=\dfrac{7}{44}$

7 0

2 years ago

Solve the equation by completing the square. x2-3x-3=0

Alina [70]

The answer is
$x = \frac{3}{2} + - \sqrt{ \frac{21}{2} }$

4 0

3 years ago

The area of a circle is 81pi square inches. what is the radius

FinnZ [79.3K]

Answer:

. r=9 inches is the answer.

7 0

3 years ago

Factor this expression.<br>-12/28b + 15/32

sertanlavr [38]

Answer:

3/4(-4/7b+5/8)

Step-by-step explanation:

3/2(-4/14b+5/16)

3/4(-4/7b+5/8)

7 0

3 years ago

Can somebody help me plz

kap26 [50]

25.05 I would think mean .05 is the change and if there is not a month cost than it would not double

5 0

4 years ago