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Jlenok [28]
4 years ago
10

The vertices of a triangle are P(-8, 1), ((-6, 8), and R(4, -3). Name the vertices of the image

Mathematics
2 answers:
-Dominant- [34]4 years ago
8 0

Answer:

P'(-8,-1)

?'(-6,-8)

R'(4,3)

Step-by-step explanation:

If you were to reflect the points across the x-axis, then the rule here would be that the x variable would stay the same while the y variable becomes the opposite.

So,

P(-8,1) = P'(-8,-1)

?(-6,8) = ?'(-6,-8)

R(4,-3) = R'(4,3)

tekilochka [14]4 years ago
6 0

Answer:

(8,1) (6,8) (-4,-3)

Step-by-step explanation:

all you do is change the sign on your x

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This monitor has a diagonal length of 19 inches and an aspect ratio of 5:4. What are the width and height of the monitor? Round
nasty-shy [4]

<em>Rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Explanation:</h2><h2 />

The aspect ratio is defined as:

<em>"The proportional relationship between the width and height of an image"</em>

It is usually expressed in a mathematical language as:

x:y \\ \\ x: \ Width \\ \\ y: \ Height

So, it is true that:

x:y=5:4 \\ \\ or: \\ \\ \frac{x}{y}=\frac{5}{4} \\ \\ \therefore x=\frac{5y}{4}

In this case, we know that the monitor has a diagonal length (D):

D=19in

So, by Pythagorean theorem:

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4}

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4} \\ \\ 361=\left(\frac{5y}{4}\right)^2+y^2 \\ \\ 361=\frac{25y^2}{16}+y^2 \\ \\ \frac{41}{16}y^2=361 \\ \\ y^2=\frac{261\times 16}{41} \\ \\ y=\sqrt{140.87} \\ \\ y=11.869in

Finding x:

x=\frac{5(11.869)}{4} \\ \\ x=14.836in

<em>Finally, rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Learn more:</h2>

Pythagorean Theorem: brainly.com/question/10182890

#LearnWithBrainly

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A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units
Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'

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