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AURORKA [14]
3 years ago
11

Please help I will mark Brainly

Mathematics
2 answers:
valina [46]3 years ago
7 0

I believe the answer is A. X-Coordinate


marissa [1.9K]3 years ago
7 0

Answer:

The answer is the d: y-coordinate

Step-by-step explanation:

Ordered pairs are in the order ( x , y ). Plug in the numbers and you see that -5 is the y coordinate.

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Tyronne worked 21 days last month he earned $79 each day how much did tyronne earn last month
krek1111 [17]
The answer is 1,659. hope i helped
3 0
3 years ago
Read 2 more answers
What is the slope of the line represented by the equation 10×+5y=4<br>a.2<br>b.1/2<br>c.-1/2<br>d.-2
VikaD [51]
Equation: 10x + 5y = 4
5y = -10x + 4

Divide the equation by 5, 
y = -2x + 4/5

Now Compare it with, y = mx + c
Here,m = -2

In short, Your Answer would be Option D

Hope this helps!
6 0
3 years ago
Can someone please help me with this I will give brainliest
IrinaK [193]

Answer:

Step-by-step explanation:

2(2x +4) - 2x = x + 18

4x +8 -2x = x +18

2x -x = 18-8

X = 10

Put the value of x in both side

Left side *+*+*+*+*+

2 ( 2*10+4)-2*10

48-20 = 28

Right side +*+*+*+*+*

X + 18

10+ 18 = 28

Mark it as Brainlist. Follow me for more answer

4 0
2 years ago
Find the product.<br> (x+2)(x−2)=
kaheart [24]

Answer:

x² - 4

Step-by-step explanation:

Step 1: Write expression

(x + 2)(x - 2)

Step 2: FOIL

x² + 2x - 2x - 4

Step 3: Combine like terms

x² - 4

8 0
3 years ago
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At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is
garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}&#10;\\\\\\&#10;\begin{cases}&#10;\frac{db}{dt}=20\\&#10;c=10\sqrt{353}\\&#10;b=80&#10;\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}&#10;\\\\\\&#10;\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

8 0
3 years ago
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