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Maurinko [17]
4 years ago
8

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

nd the probability of x successes given the probability p of success on a single trial. Round to three decimal places. nequals=​4; xequals=​3; pequals=one sixth 1 6 A. 0.004 B. 0.023 C. 0.015 D. 0.012
Mathematics
1 answer:
Nana76 [90]4 years ago
8 0

Answer:

C. 0.015

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we want:

P(X = 3) when n = 4, p = \frac{1}[6}

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{4,3}.(\frac{1}{6})^{3}.(\frac{5}{6})^{1} = 0.015

So the correct answer is:

C. 0.015

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