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Tanya [424]
3 years ago
10

A construction crew built 7 1/2 miles of road in 3 1/8 days.

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
2 2/5 per day I’m pretty sure ( 3 1/8 / 7 1/2)
posledela3 years ago
4 0

Answer:

If you think numbers with fractions are annoying, consider transforming the number into fractions!

Step-by-step explanation:

7 1/2 is (14+1)/2, and 3 1/8 is (24+1)/3. Not you have 15/2 miles for 25/3 days and by dividing them you get 0.9 miles a day

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If a car factory checks 360 cars and 8 of them have defects, how many will have defects out of 1260?
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You should expect 28 defected cars.
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3 years ago
Me QR goes through points Q(0, 1) and R(2, 7). Which equation represents line QR?
maks197457 [2]

We write the equation in the form of directional.

y -1 = 6x               ⇔    y = 6x + 1

y - 1 = 3x              ⇔    y = 3x + 1

y - 7 = 2x - 6         ⇔    y = 2x - 6 + 7

                                    y = 2x + 1

y - 7 = x - 2           ⇔    y = x - 2 + 7

                                    y = x + 5

Equations cleverly arranged .

Point Q = (0,1)  

b factor , not only fits the last equation

In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1

Answer b

We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function

The result of equations confirmed our choice Answer b

3 0
2 years ago
Write 2^-3=1/8 in logarithmic form
tensa zangetsu [6.8K]

That is your answer if it is wrong i will try to fix it

6 0
4 years ago
A monomial that Is just a real number is called
ludmilkaskok [199]
I believe the term is "constant".
5 0
3 years ago
Determine an equation of a Quadratic function
Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is  

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1)   0 =    4a + 2b + c

(2)  0 = 36a + 6b + c

(3) 12 =   9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6)  0 = 8a + b

(7) -4 = 9a  - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

    0 = -32 + b

(9) b =  32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0
3 years ago
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