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AlexFokin [52]
2 years ago
13

Click on the least amount of rainfall.

Mathematics
1 answer:
Andreas93 [3]2 years ago
5 0

The least amount is the smallest amount, 1/8.

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Step-by-step explanation:

8 0
2 years ago
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1. Find the length of X (in the picture) plssss I need help.​
Vedmedyk [2.9K]

Step-by-step explanation:

\frac{5}{4}  =  \frac{x}{6}  \\ 4x = 30 \\ x = 7.5

3 0
3 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
3 years ago
Using the powers of 10, which would be the first to subtract when 742 divided by 61?
cestrela7 [59]

Answer:

610

61*10 = 610

You can then subtract that from 742.

4 0
3 years ago
If someone could help me with number 26...
Volgvan
Given:
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0

Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0
\text{sec x} =  \sqrt{\text{2 sec x}-1}

Then square both side to remove the root
\text{sec}^2 x= \text{2 sec x}-1

After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0

Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
\dfrac{1}{\text{cos x}} = 1
cos x = 1
cos x = cos 0°
x = 0°
8 0
3 years ago
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