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3 years ago

Pls help. Don't answer if you don't know.

Mathematics

1 answer:

Pavel [41]3 years ago

5 0

Answer:

The answer is C.

Step-by-step explanation:

It is 180÷5=36. n is basically just symbolizes 180, and b is the number of candles in each box.

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Please help asap 25 pts

mart [117]

Answer:

Range = 0,1,2,3,4

Step-by-step explanation:

The range is the set of y values for every corresponding x. -4 is a member of the domain (x values) and that means A C and D are all incorrect.

B is the only one that does not begin with - 4 so B is the right answer.

7 0

4 years ago

Read 2 more answers

Kimber is thinking about buying a four-wheeler that is priced at $6,700. However, he

Semenov [28]

Answer:

1340 is the amount kimber needs

5 0

3 years ago

The probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48 and of owning both is 0.45.

Vera_Pavlovna [14]

Answer:

The probability that the middle school student owns a skateboard or a bicycle is 0.61.

Step-by-step explanation:

We are given that the probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48, and owning both is 0.45.

A middle school student is chosen at random.

Let the probability of student owning a skateboard = P(S) = 0.58

The probability of student owning a bicycle = P(B) = 0.48

The probability of student owning both = P(S $\bigcap$ B) = 0.45

Now, the probability that the middle school student owns a skateboard or a bicycle is given by = P(S $\bigcup$ B)

P(S $\bigcup$ B) = P(S) + P(B) - P(S $\bigcap$ B)

= 0.58 + 0.48 - 0.45

= 0.61

Hence, the probability that the middle school student owns a skateboard or a bicycle is 0.61.

4 0

3 years ago

Toyland is having a sale. All items are 20% off. How much will you save on an item that usually sells for $95?

Olegator [25]

Answer:

Step-by-step explanation:

To find 20% of 95 multiply 95 by 0.20, p5 x 0.20=19

3 0

3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

4 years ago