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Naddik [55]
4 years ago
9

Mitchell poured the contents of a completely filled cone into an empty cylinder, and the cylinder became two-thirds full. The cy

linder had a radius of 5 cm and a height of 15 cm. What were possible dimensions of the cone? Use 3.14 to approximate pi.
a. h = 5 cm; r = 15 cm
b. h = 7.5 cm; r = 10 cm
c. h = 10 cm; r = 7.5 cm
d. h = 15 cm; r = 5 cm
Mathematics
1 answer:
iogann1982 [59]4 years ago
8 0
Answer: B. h = 7.5 cm ; r = 10 cm
Given:
Cylinder 
Cone

Volume of Cylinder = π r² h
= 3.14 * (5cm)² * 15cm
= 3.14 * 25cm² * 15cm
= 1,177.50 cm³

Volume of the cone = 1,177.50 cm³ * 2/3
= 2355 cm³ ÷ 3 
= 785 cm³

Volume of the cone = π r² h/3

a) 3.14 * 15² * 5/3 = 1177.50 cm³
b) 3.14 * 10² * 7.5/3 = 785 cm³
c) 3.14 * 7.5² * 10/3 = 588.75 cm³
d) 3.14 * 5² * 15/3 = 392.50 cm³
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Range: \{5.3,3.3,-2.7\}

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Explanation:

The coordinates (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) are plotted in the graph. The image of the graph is attached below.

The domain of a relation is the set of all x-values for which the function is well defined. Thus, the domain are \{3.3,-1.7,-4.7\}

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The relation (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) is not a function since, -4.7 has two different y-values. By definition of function, the function cannot have two different y-values for the same x-value.

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Answer:

Step-by-step explanation:

t5 = a + (5-1)d

t5 = a + 4d

40 = a + 4d

t3 = a + 2*d

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Start with the seventh term which has 2 equal answers

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d  = 7

==================

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===================

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Interesting question. Thanks for posting

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