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Anni [7]
3 years ago
8

What is the mean absolute deviation (MAD) of the data set?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

\frac{16}{5}

Step-by-step explanation:

The formula for MAD is  attached in the pic below.

<em>X_i are all the x values</em>

<em>x bar is the mean (sum of all the numbers divided by the number of numbers)</em>

<em>n is the number of numbers</em>

<em />

Basically, <em>we subtract the mean (x bar) from each of the values and take the absolute value of it and SUM all of them. Then we divide by the number of numbers.</em>

<em />

Thus, mean = \frac{2+6+8+12+12}{5}=\frac{40}{5}=8

Now, \frac{|2-8|+|6-8|+|8-8|+|12-8|+|12-8|}{5}\\=\frac{6+2+0+4+4}{5}\\=\frac{16}{5}

The MAD is  \frac{16}{5}

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An attacker at the base of a castle wall 4 m high throws a rock straight up with speed 7.5 m/s from a height of 1.5 m
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Answer:

a) Yes, b) v\approx 2.686\,\frac{m}{s}, c) v_{o} \approx 7.002\,\frac{m}{s}

Step-by-step explanation:

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\Delta y = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(7.5\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}

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b) The speed when the rock reaches the top of the wall:

v = \sqrt{\left(7.5\,\frac{m}{s} \right)^{2}+2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m)}

v\approx 2.686\,\frac{m}{s}

c) The initial speed required so that stone does not exceed the top of the wall is:

v_{o} = \sqrt{\left(0\,\frac{m}{s} \right)^{2}-2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m) }

v_{o} \approx 7.002\,\frac{m}{s}

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