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2 years ago

7

How many hundreds are all in the number of 44,813 ??

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer: Well, I thought about it and I was like, Well 813 right? Then I realized the question and was like: Nvm lol (Hope you find the answer!)

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Please help me thanks

PilotLPTM [1.2K]

6x + 45 + 3x = 180
9x - 45 = 180
9x = 135
x = 15

8 0

2 years ago

As professional sports teams become more and more profitable, the salaries paid to the players have also increased. In fact, man

lesya [120]

Answer: Median

Step-by-step explanation:

some sport superstars are paid extremely huge salaries, but this is not always the case for all spott stars. Since the mean is largerly influenced by the large salaries the data becomes unrelaible When estimating the center but reliable when it comes down to representing the center. With this reason is why the median would be considered.

7 0

2 years ago

johhny borrowed $15 per month from his mom to pay for his school supplies at the end of the course he owed his mom $135 how many

dusya [7]

9 months,
$135 \ \div 15 = 9$

6 0

2 years ago

Read 2 more answers

IF U ANSWER CORRECTLY I MARK U BRAINLIEST

Andreyy89

Answer:

B and C

Step-by-step explanation:

B: Normally 3/7 would be bigger, but since it's negative -2/7 is greater than -3/7.

C: 0 is greater than anything negative.

5 0

2 years ago

Read 2 more answers

Two owners of a cattle ranch, Jo and Val, want to find the average weight for the ranch's 200 cows. Instead of weighing all of t

Zolol [24]

Answer:

The value is $E =19.6$

Step-by-step explanation:

From the question we are told that

The mean of Jo cows is $\= x_1 = 1350$

The standard deviation of Jo cow is $s_1 = 50$

The mean of Val cows is $\= x_2 = 1420$

The standard deviation of Val cows is $s_2 = 50$

The sample size for both Val and Jo is n = 25

Let assume that the level of significance is $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

Hence margin of error for Jo is

=> $E = 1.96 * \frac{50}{\sqrt{25} }$

=> $E =19.6$

4 0

2 years ago