Please help with numbers 5 and 7!

Mathematics

1 answer:

natta225 [31]3 years ago

5 0

The answer for number 5 is= 6+2 bc 6×2=12 and 6+2=8
and I'm sorry I have no idea for number 7

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ohaa [14]

2 evens is an positive
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8 0

3 years ago

Use substitution to solve the sy 2x+3y = 19 x = 2y-1 Solve for x and y

svp [43]

Answer: Y=3, X=5

Step-by-step explanation:

2(2y-1) + 3y=19

4y-2+ 3y=19

7y=21

Y=3

Plug in y in the second equals

X=2(3) -1

X=6-1

X=5

Hope this helps!

8 0

3 years ago

the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

System of equations, variables, hardcover version, paperback version, books

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$