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Kaylis [27]
3 years ago
15

Which angle forms a linear pair with ∠ABD

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

I believe its angle DBC

Step-by-step explanation:

A linear pair has to equal 180 degrees together

Soloha48 [4]3 years ago
4 0

Answer:

fbc

Step-by-step explanation: that is the closest answer

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Which of the following expressions is equivalent to 6m - 10?
Natasha_Volkova [10]
Just calculate this:
A) 2(3m + 5) = 6m + 10 - incorrect
B) -2(5 - 3m) = -10 + 6m - could be correct
C) 2(3m - 10) = 63 - 20 - incorrect

So <u>the correct answer has to be B</u>: -10 + 6m is the same as 6m - 10.
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Answer:

the third one is the answer

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480 + 192 = 672 students total
16 + 12 = 28 classrooms total
672/28 = 24 students per room
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ERJENT PLS HELP<br> |3x - 4| &lt; 7<br> what’s the inequality answer?
Mars2501 [29]

Answer:

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3 0
3 years ago
Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
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