Find the slope of the line -x = -3y + 9

Mathematics

2 answers:

ruslelena [56]3 years ago

7 0

The slope would be M= 1/3

givi [52]3 years ago

5 0

Answer:

m= 1/3

Step-by-step explanation:

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2y+5y-3yTo the second power

gogolik [260]

Answer:16y I think

Step-by-step explanation:

Take out the y, 2+5-3 is 4, and to the second power is multiplying 4 twice, so 16. theyre all have the same variable to the right, so 16y

7 0

3 years ago

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Which equation represents a line with a slope of 5/2and a y-intercept of -8/3

Ludmilka [50]

Answer:

y=5/2x-8/3

Step-by-step explanation:

The equation is y=mx+b

M is the slope and b is the y-intercept.

7 0

3 years ago

What is -3/2 - 7/4 + 1/8

Eddi Din [679]

Answer:

3/8

Step-by-step explanation:

-3/2 can change to -12/8

7/4 can change to 14/8

1/8 stays the same

-12/8 + 14/8 = 2/8 + 1/8 = 3/8

3 0

3 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$