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svlad2 [7]
3 years ago
12

Part A: how many solutions dose the pair of equations for lines A and B have?

Mathematics
2 answers:
Ede4ka [16]3 years ago
8 0

Any line can be expressed in the form y=mx+b where m is the slope and b is y intercept.

Two lines can either be parallel ,overlap or meet at one point .Let us look at different cases :

1)When two lines are parallel they do not intersect at any point and hence the system of equations have no solution.

2) When two lines overlap each other then the two lines touch each other at infinite number of points and we say the system of equations have infinite solutions.

3) When two lines intersect each other at one point we say the system of equation has one solution.

Part A:

The given lines are intersecting at one point so we have one solution.

Part B:

The point of intersection is the solution to the system of equations .In the graph the point of intersection of the lines is (4,4)

Solution is (4,4)

Vera_Pavlovna [14]3 years ago
5 0

Part A: The number of solutions for a set of linear equations (in this case only two of them, represented as two lines) is the number of points of intersection. For linear equations in 2-dimensions the only possible answers are zero, one and infinity. In this case it is clearly one.

Part B: By inspection, the point of intersection, and thus the solution to the system of equations, is (4,4).

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A baseball team plays in a stadium that holds 62000 spectators. With the ticket price at $11, the average attendance has been 27
sasho [114]

Answer:

$15.625

Step-by-step explanation:

Let the revenue collected be R and price per spectator be p then the number of spectators be N. Therefore

R=Np

Using equation of slope of y=mx +c where m is gradient and c is y-intercept

When p=$11, N=27000 and when p=$8, N=31000

The gradient, m will be

m=\frac {31000-27000}{8-11}= -1333.33

To get the y-intercept

N=-1333.33p+c

When spectator number n is 27000, the price p is $11

27000=-1333.33(11)+c hence we solve c

c=27000+(11*1333.33)= 41666.67

Therefore, the linear equation is

N=-1333.33p+ 41666.67

Substituting the linear equation into R=Np we obtain

R=p(-1333.33p+41666.67)

R=-1333.33p^{2}+41666.67p

To obtain maximum revenue, we differentiate the above with respect to price hence obtain

0=2*-1333.33p+41666.67

p=-\frac {41666.67}{2(-1333.33)}= 15.625

Therefore, the price that maximizes revenue is $15.625

4 0
3 years ago
Who do you solve 10=z+6 as a one step equation
ANTONII [103]
For this question, all you have to do is subtract 6 from 10 to get 4. 4 + 6 is 10. z = 4.
4 0
3 years ago
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What is 2m+12=3m-31?
sukhopar [10]

Answer:

m=43

Step-by-step explanation:

2m-3m=-31-12

-m=-43

m=43 (Because if we divide -1m/-1 = 1m and -43/-1 = 43)

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3 years ago
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Answer:

(2,0) and (4,0)

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The roots of the parabola are the points where the value of the function is zero, i.e., where the graph crosses the x-axis.

(2,0) and (4,0)

7 0
3 years ago
Rate of change from the line
Ghella [55]

\textbf{Answer:}

\frac{-1}{4}

\textbf{Step-by-step explanation:}

\frac{y2 - y1}{x2 - x1}

\textrm{Use the formula above to determine the rate of change}

\frac{1 - 2}{4 - 0} \rightarrow\frac{-1}{4}

\textrm{The rate of change of this line is } \frac{-1}{4}

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