Answer:
x=6 since 6 is not being squared but to the power of zero
Step-by-step explanation:
Let's assume x = apple juice, y = orange juice, and z = cranberry juice

<u>x : y : z = 3/4 : 1/10 : 3/20</u>
If we were to make them all in the same denominator, x : y : z = 15/20 : 2/20 : 3/20.

I think the equation would be 101=4.50b+25 where b is equal to the the maount of bracelets and 25 dollars for the materials and 101 is how much she had at the end of the month
So you would subract 25 from each sides
So 25-25 you cancel off and on the other side 101-25=76
Then, it would be 4.50b=76 so you divide 4.50 on each side and get b=17
Answer:
P(X > 126) = 0.2119
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

P(X > 126) is the 1 subtracted by the pvalue of Z when X = 126. So


[tez]Z = 0.8[/tex]
[tez]Z = 0.8[/tex] has a pvalue of 0.7881.
P(X > 126) = 1 - 0.7881 = 0.2119
Answer:
D. about 8.5 mi
Step-by-step explanation:
To go from Aesha to Josh, you go 6 units right and 6 units up.
Each unit is a mile, so you go 6 miles right and 6 miles up.
Think of each 6 mile distance as a leg of a right triangle, and the direct distance from one place to the other as the hypotenuse of the right triangle. Use the Pythagorean theorem to find the length of the hypotenuse.
a^2 + b^2 = c^2
The 6-mile legs are a and b. c is the hypotenuse.
(6 mi)^2 + (6 mi)^2 = c^2
c^2 = 36 mi^2 + 36 mi^2
c^2 = 72 mi^2
c = sqrt(72) mi
c = sqrt(36 * 2) mi
c = 6sqrt(2) mi
c = 6(1.4142) mi
c = 8.5 mi